Solve the system
-3x-y=-10
4x-4y=8
To solve this system of equations, we can use the method of substitution.
First, we solve the first equation for y in terms of x:
-3x - y = -10
y = -3x + 10
Now we substitute this expression for y into the second equation:
4x - 4(-3x + 10) = 8
4x + 12x - 40 = 8
16x - 40 = 8
16x = 48
x = 3
Now that we have found x, we can substitute it back into the first equation to find y:
-3(3) - y = -10
-9 - y = -10
-y = -1
y = 1
Therefore, the solution to the system of equations is x = 3 and y = 1.