A group of art students are painting a mural on a wall. The rectangular wall has dimensions of (6x + 7) by (8x + 5) and they are planning the mural to be (x + 4) by (2x + 5). What is the area of the remaining wall after the mural has been painted? (1 point)
To find the area of the remaining wall after the mural has been painted, we first need to find the areas of both the wall and the mural.
Area of the wall:
(6x + 7)(8x + 5) = 48x^2 + 30x + 42x + 35 = 48x^2 + 72x + 35
Area of the mural:
(x + 4)(2x + 5) = 2x^2 + 5x + 8x + 20 = 2x^2 + 13x + 20
Subtract the area of the mural from the area of the wall to find the area of the remaining wall:
(48x^2 + 72x + 35) - (2x^2 + 13x + 20)
46x^2 + 72x + 35 - 2x^2 - 13x - 20
44x^2 + 59x + 15
Therefore, the area of the remaining wall after the mural has been painted is 44x^2 + 59x + 15.
46x2 + 73x + 15
46 x 2 + 73 x + 15 48x2 + 86x + 35
48 x 2 + 86 x + 35 2x2 + 13x + 20 2 x 2 + 13 x + 20
50x2 + 99x + 55
I apologize for the error in my calculation. Let's correct it:
Area of the wall: (6x + 7)(8x + 5) = 48x^2 + 30x + 42x + 35 = 48x^2 + 72x + 35
Area of the mural: (x + 4)(2x + 5) = 2x^2 + 5x + 8x + 20 = 2x^2 + 13x + 20
Subtract the area of the mural from the area of the wall to find the area of the remaining wall: (48x^2 + 72x + 35) - (2x^2 + 13x + 20) = 46x^2 + 59x + 15
Therefore, the correct area of the remaining wall after the mural has been painted is 46x^2 + 59x + 15. Thank you for pointing out the mistake.