4. Han and Clare walk towards each other at a constant rate, meet up, and then continue past each other in opposite directions. We will call the position where they meet up 0 feet and the time when they meet up 0 seconds.
Han's velocity is 4 feet per second.
Clare's velocity is -5 feet per second.
a. Where is Han 10 seconds before they meet up?
b. When is Han at the position -10 feet from the meeting place?
c. When is Claire at the position -10 feet from the meeting place?
a. Han is moving at a rate of 4 feet per second towards the meeting place. Therefore, 10 seconds before they meet up, Han is 40 feet away from the meeting place.
b. To find when Han is at the position -10 feet from the meeting place, we set up the following equation:
4t = -10
t = -10/4
t = -2.5 seconds
Therefore, Han is at the position -10 feet from the meeting place 2.5 seconds after they meet up.
c. Clare is moving at a rate of -5 feet per second towards the meeting place. Therefore, to find when she is at the position -10 feet from the meeting place, we set up the following equation:
-5t = -10
t = 10/5
t = 2 seconds
Therefore, Clare is at the position -10 feet from the meeting place 2 seconds before they meet up.