A water well drilling rig has dug to a height of -60 feet after one full day of continuous use. (24 hours)
1. Assuming the rig was drilled at a constant rate, what was the height of the drill after 15 hours?
2. If the rig has been running constantly and is currently at a height of -147.5 feet, for how long has the rig been running?
3. At this rate, how many hours will it take until the drill reaches -250 feet?
1. The rig dug 60 feet in 24 hours, so it dug 60/24 = 2.5 feet per hour. After 15 hours, the drill would be at a height of 2.5 ft/hr * 15 hrs = 37.5 feet.
2. To determine how long the rig has been running, we can first calculate how many feet it dug in total to reach a height of -147.5 feet from an initial height of 0 feet. It dug 60 feet in the first 24 hours, then 147.5 feet - 60 feet = 87.5 feet from the initial height of -60 feet. Thus, it took 87.5 feet / 2.5 feet per hour = 35 hours to reach a height of -147.5 feet.
3. To find out how many hours it will take for the drill to reach -250 feet, we can use the same rate of 2.5 feet per hour. The height difference from -147.5 feet to -250 feet is 250 feet - 147.5 feet = 102.5 feet. Thus, it will take 102.5 feet / 2.5 feet per hour = 41 hours to reach a height of -250 feet.