Jordan has some nickels and some dimes. He has no less than 15 coins worth no more than $1.25 combined. If Jordan has 9 nickels, determine the maximum number of dimes that he could have.
Let x be the number of dimes Jordan has.
The value of 9 nickels is 9 * $0.05 = $0.45.
The value of x dimes is x * $0.10 = $0.10x.
The total value of the coins is $0.45 + $0.10x.
Since the total value is no more than $1.25, we have:
$0.45 + $0.10x ≤ $1.25
$0.10x ≤ $1.25 - $0.45
$0.10x ≤ $0.80
x ≤ 8
Therefore, the maximum number of dimes Jordan could have is 8.