How many liters of hydrogen at STP can be produced by the reaction of 4.15 g of zinc with hydrochloric acid:
Zn + 2HCl -> ZnCl2 + H2
1.41 L of H2?
To find out how many liters of hydrogen can be produced, we need to use the information provided in the balanced chemical equation and apply stoichiometry.
1. Determine the molar mass of zinc (Zn) and hydrogen (H2):
- The molar mass of Zn is 65.38 g/mol.
- The molar mass of H2 is 2.02 g/mol.
2. Convert the mass of zinc (4.15 g) to moles using its molar mass:
- Moles of Zn = mass of Zn / molar mass of Zn
- Moles of Zn = 4.15 g / 65.38 g/mol
3. From the balanced equation, we know that 1 mole of Zn produces 1 mole of H2. Therefore, the number of moles of hydrogen produced will be the same as the number of moles of zinc consumed.
4. Calculate the volume of hydrogen produced using the ideal gas law at STP (Standard Temperature and Pressure):
- The molar volume of a gas at STP is 22.4 L/mol.
- Volume of H2 = Moles of H2 x Molar volume at STP
- Volume of H2 = Moles of Zn x 22.4 L/mol
5. Substitute the value of moles of Zn obtained from step 2 into the equation from step 4 to get the volume of hydrogen produced in liters.
Remember to perform the calculations:
Moles of Zn = 4.15 g / 65.38 g/mol
Volume of H2 = Moles of Zn x 22.4 L/mol
By substituting the values, you can find the answer to the question.
for every mole of zinc, you get 22.4liters of H2
How many moles of zinc is 4.15g?
that doesn't make sense to me... can you give me a step by step walk through?
Zn + 2HCl ==> ZnCl2 + H2
moles Zn = 4.15/molar mass Zn = xx.
xx moles Zn will produce xx moles H2 (since 1 mole Zn produces 1 mole H2 according to the equation.)
xx moles H2 x (22.4 L/1 mol) = yy liters H2. Voila!