To show how to solve the equation, create two functions and find their intersection points. What two functions can be used to solve the following equation, and what is their solution set? 10−x2=x+4 (1 point) Responses
g(x)=x+4 , f(x)=10+x2 , {−3,2}
g(x)=x+4 , f(x)=10−x2 , {1,6}
f(x)=10−x2 , g(x)=x+4 , {−3,2}
f(x)=10+x2 , g(x)=x+4 , {−3,1}
f(x) = 10 - x^2
g(x) = x + 4
To find the intersection points, set f(x) equal to g(x):
10 - x^2 = x + 4
Rearrange the equation:
x^2 + x - 6 = 0
Factor the quadratic equation:
(x + 3)(x - 2) = 0
Therefore, x = -3 or x = 2
The solution set is {-3, 2}.
So the correct response is: f(x)=10−x^2 , g(x)=x+4 , {−3,2}