find the distance of line A. round your answer to the nearest tenth.
line A = (-10, 10) and (-5, 7)
To find the distance of line A, we can use the distance formula:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
Using the points given:
x1 = -10, y1 = 10
x2 = -5, y2 = 7
Distance = √((-5 - (-10))^2 + (7 - 10)^2)
Distance = √((5)^2 + (-3)^2)
Distance = √(25 + 9)
Distance = √34
Distance ≈ 5.8
So, the distance of line A is approximately 5.8 units.
find the missing value that make the equation true
6^-5 * 6^? = 6^10
the "?" symbol in the equation should be: ____
To find the missing value that makes the equation true, we can use the properties of exponents. When multiplying two numbers with the same base, we can add the exponents.
Using this property, we can rewrite the equation as:
6^(-5 + ?) = 6^10
We want the expressions on both sides to be equal, so the exponents must be equal as well:
-5 + ? = 10
Now, we can solve for the missing value:
? = 10 + 5
? = 15
Therefore, the missing value that makes the equation true is 15. The completed equation is:
6^-5 * 6^15 = 6^10