If there is a 60% If your favorite team wins the game, what is the percent chance that they do not win?
The percent chance that your favorite team does not win the game would be 100% - 60% = 40%.
There is a jar that contains 8 marbles and 5 of them are blue. If you were to draw 2 marbles (with replacement) randomly what is the probability that both the marbles are not blue? Write your answer as a fraction. You do not need to simplify your faction. Click Here for Help Video
To find the probability that both marbles drawn are not blue, we first need to find the probability of drawing a non-blue marble on each draw.
The probability of drawing a non-blue marble on the first draw is 3/8 (since there are 3 non-blue marbles out of a total of 8 marbles).
Since we are drawing with replacement, the probability of drawing a non-blue marble on the second draw is also 3/8.
To find the overall probability that both marbles drawn are not blue, we multiply the probabilities of each individual draw:
(3/8) * (3/8) = 9/64
Therefore, the probability that both marbles drawn are not blue is 9/64.
John has three chances of throwing and hitting the target to win the prize. One hit wins John the prize. What is the probability of John not winning if any given throw has a 60% chance of hitting the target?
The probability of hitting the target on any given throw is 60%, so the probability of not hitting the target on any given throw is 40%.
To find the probability of John not winning the prize in all three throws, we need to calculate the probability of not hitting the target in all three throws.
Since each throw is independent, we can simply multiply the probabilities of not hitting the target for each throw:
0.4 (probability of not hitting the target) * 0.4 * 0.4 = 0.064
Therefore, the probability of John not winning the prize in all three throws is 6.4%.