A ball is projected with velocity 10m/s at an angle of 30 degree with the horizontal surface.the speed of the ball after 1s will be (use g=10m/s square)
To find the speed of the ball after 1 second, we need to break down the initial velocity into horizontal and vertical components.
The horizontal component of the initial velocity can be calculated using the formula:
Vx = V * cos(θ)
where V is the initial velocity (10 m/s) and θ is the angle of projection (30 degrees).
Vx = 10 * cos(30) = 10 * sqrt(3)/2 = 5√3 m/s
The vertical component of the initial velocity can be calculated using the formula:
Vy = V * sin(θ)
Vy = 10 * sin(30) = 10 * 0.5 = 5 m/s
Now, we can calculate the speed of the ball after 1 second by using the equation for vertical motion:
Vf = Vi + gt
where Vi is the initial vertical velocity (5 m/s), g is the acceleration due to gravity (10 m/s^2), and t is the time in seconds (1 second).
Vf = 5 + 10*1 = 5 + 10 = 15 m/s
Therefore, the speed of the ball after 1 second will be 15 m/s.