Find the​ vertical, horizontal, and oblique​ asymptotes, if​ any, for the following rational function. R(x)= (5x^2-19x-4)/ 2x^2-7x-4

Find the oblique asymptotes.

To find the vertical asymptotes, set the denominator equal to zero and solve for x:

2x^2 - 7x - 4 = 0

This quadratic equation can be factored as:

(2x + 1)(x - 4) = 0

Setting each factor equal to zero gives:

2x + 1 = 0 or x - 4 = 0
x = -1/2 x = 4

Therefore, the vertical asymptotes are x = -1/2 and x = 4.

To find the horizontal asymptote, compare the degrees of the numerator and denominator. Since they are both quadratic terms, divide the leading coefficients to find the horizontal asymptote:

Horizontal asymptote: y = 5/2

To find the oblique asymptote, perform long division of the numerator by the denominator:

5x - 4
____________________
2x^2 - 7x - 4 | 5x^2 - 19x - 4
- (5x^2 - 17x + 8)
______________
-2x - 12

This gives a quotient of 5 with a remainder of (-2x - 12)/(2x^2 - 7x - 4).

Thus, the oblique asymptote is y = 5 with a slant of -2x - 12 over the quadratic term.