represented by the quadratic equation h16t² + 64t+ 80.
After how many seconds will the object hit the ground?
A 29 seconds
B 6.4 seconds
C 5.0 seconds
D 8.0 seconds
To find when the object will hit the ground, we need to solve for t when h(t) = 0.
h(t) = 16t^2 + 64t + 80
Setting h(t) = 0:
0 = 16t^2 + 64t + 80
Dividing the equation by 16 to simplify:
0 = t^2 + 4t + 5
Now, we can factorize this quadratic equation:
0 = (t + 1)(t + 5)
Setting each factor to zero:
t + 1 = 0
t = -1
t + 5 = 0
t = -5
Since time cannot be negative, the object will hit the ground after 5 seconds. Therefore, the answer is:
C 5.0 seconds