How much quantity of heat energy is required to change 7.4kg of ice at 0°C into water at the same temperature? [Lf=306,000J/kg]
The heat energy required to change ice at 0°C into water at the same temperature can be calculated using the formula:
Q = m * Lf
Where:
Q = heat energy (in joules)
m = mass of the substance (in kg)
Lf = latent heat of fusion (in joules/kg)
Given:
m = 7.4 kg
Lf = 306,000 J/kg
Therefore,
Q = 7.4 kg * 306,000 J/kg
Q = 2,264,400 J
Therefore, the quantity of heat energy required to change 7.4kg of ice at 0°C into water at the same temperature is 2,264,400 joules.