(2y-7)(3y+5)
Expanding the expression (2y-7)(3y+5) using the distributive property:
= 2y(3y) + 2y(5) - 7(3y) - 7(5)
= 6y^2 + 10y - 21y - 35
= 6y^2 - 11y - 35
Therefore, (2y-7)(3y+5) = 6y^2 - 11y - 35.
= 2y(3y) + 2y(5) - 7(3y) - 7(5)
= 6y^2 + 10y - 21y - 35
= 6y^2 - 11y - 35
Therefore, (2y-7)(3y+5) = 6y^2 - 11y - 35.