Divide
2x^5/3y^2 ÷ 8y^-3/3x^-7
The quotient is simplified to:
X cannot equal:
Y cannot equal:
(2x^5/3y^2) ÷ (8y^-3/3x^-7)
First, simplify the division by multiplying by the reciprocal:
(2x^5/3y^2) * (3x^-7/8y^-3)
= 2x^5 * x^-7 / 3y^2 * 8y^-3
= 2x^-2 / 24y^-1
= x^-2 / 12y^-1
= x^-2 / 12/y
Now, rewrite the division as multiplication by changing the sign of the exponent in the denominator:
x^-2 * y / 12
The quotient is simplified to:
1/(12x^2y)
Therefore, x cannot equal 0 and y cannot equal 0.