What volume (mL) of 0.137 M NaOH is required to neutralize 14.8 mL of 0.316 M HCl?
To determine the volume of NaOH needed to neutralize the HCl, we can use the formula:
M1V1 = M2V2
Where:
M1 = molarity of HCl = 0.316 M
V1 = volume of HCl = 14.8 mL
M2 = molarity of NaOH = 0.137 M
V2 = volume of NaOH (unknown)
Plugging in the values:
(0.316)(14.8) = (0.137)(V2)
4.6768 = 0.137V2
V2 = 4.6768 / 0.137
V2 ≈ 34.2 mL
Therefore, approximately 34.2 mL of 0.137 M NaOH is required to neutralize 14.8 mL of 0.316 M HCl.