What volume (mL) of a 4.81 M lead nitrate solution must be diluted to 384 mL
to make a 1.00 M
solution of lead nitrate?
Let V be the volume of the 4.81 M lead nitrate solution that needs to be diluted.
Using the formula for dilution:
M1V1 = M2V2
(4.81 M)V = (1.00 M)(384 mL)
4.81V = 384
V = 384 / 4.81
V ≈ 79.83 mL
Therefore, approximately 79.83 mL of the 4.81 M lead nitrate solution must be diluted to 384 mL to make a 1.00 M solution of lead nitrate.