Two similar cuboids half corresponding widths of the 11 cm and 9 cm find the ratio of the surface area Hindi surface area of the large cuboid 363cm² find the surface area of a smaller cuboid
First, let's find the dimensions of the two similar cuboids:
Let the dimensions of the larger cuboid be l, h, and w, and the dimensions of the smaller cuboid be 1/2l, h, and 1/2w.
Given that the smaller cuboid has half the corresponding width of the larger cuboid, we have:
1/2w = 9 cm
w = 2*9 = 18 cm
1/2l = 11 cm
l = 2*11 = 22 cm
Now, we can find the surface areas of the two cuboids:
Surface area of the larger cuboid = 2lw + 2lh + 2wh
= 2*22*18 + 2*22*11 + 2*18*11
= 792 + 484 + 396
= 1672 cm²
Given that the surface area of the smaller cuboid is 363 cm², we can find the ratio of the surface areas:
363 / (1672/2) = 363 / 836 = 0.4346
Therefore, the ratio of the surface area of the smaller cuboid to the surface area of the larger cuboid is 0.4346.