The mean weight of a herd of white-tailed deer is 140.3 pounds, with a standard deviation of 7.2 pounds. What is the probability that a randomly selected deer weighs more than 149 pounds?
I apologize for the mistake in my previous response. Let's correct that calculation.
To find the probability that a randomly selected deer weighs more than 149 pounds, we need to calculate the z-score using the formula:
z = (X - μ) / σ
Where:
X = 149 pounds
μ = 140.3 pounds
σ = 7.2 pounds
z = (149 - 140.3) / 7.2
z = 1.2083
Next, we look up the probability of z = 1.2083 in the standard normal distribution table or use a calculator to find the area under the curve to the right of this z-score.
The probability of a z-score of 1.2083 is approximately 0.1131.
Therefore, the probability that a randomly selected deer weighs more than 149 pounds is 0.1131, or 11.31%.
Thank you for pointing out the error, and I appreciate your understanding.
To find the probability that a randomly selected deer weighs more than 149 pounds, we need to calculate the z-score for 149 pounds and then find the area under the normal distribution curve to the right of that z-score.
First, we calculate the z-score using the formula:
z = (X - μ) / σ
Where:
X = 149 pounds
μ = 140.3 pounds
σ = 7.2 pounds
z = (149 - 140.3) / 7.2
z = 0.12083
Next, we look up the probability of z = 0.12083 in the standard normal distribution table or use a calculator to find the area under the curve to the right of this z-score.
The probability of a z-score of 0.12083 is approximately 0.4515.
Therefore, the probability that a randomly selected deer weighs more than 149 pounds is 0.4515, or 45.15%.