A beaker contains 238 mL
of a 5.42 M
HCl(aq)
solution. Determine the new concentration of the solution after it is diluted by adding 139 mL
of water to the beaker.
To determine the new concentration of the solution after dilution, we can use the formula:
M1V1 = M2V2
where:
M1 = initial concentration of the solution
V1 = initial volume of the solution
M2 = final concentration of the solution
V2 = final volume of the solution
Given:
M1 = 5.42 M
V1 = 238 mL
V2 = 238 mL + 139 mL = 377 mL (after adding water)
Now we can plug in the values and solve for M2:
5.42 M x 238 mL = M2 x 377 mL
M2 = (5.42 M x 238 mL) / 377 mL
M2 = 3.41 M
Therefore, the new concentration of the HCl(aq) solution after it is diluted by adding 139 mL of water is 3.41 M.