Determine the mass of chloride ( MW
= 35.45 g/mol
) in grams present in 100 mL
of a 0.227 M
solution of aqueous GaCl3
(gallium(III) chloride).
To determine the mass of chloride present in 100 mL of 0.227 M GaCl3 solution, we first need to calculate the number of moles of GaCl3 present in the solution.
From the given concentration of the solution:
0.227 moles of GaCl3 are present in 1 liter of solution.
So, in 100 mL (0.1 L) of solution, the number of moles of GaCl3 can be calculated as:
0.227 moles/L * 0.1 L = 0.0227 moles of GaCl3
Since GaCl3 is a 1:3 stoichiometry, there are 3 moles of chloride ions (Cl-) for every 1 mole of GaCl3. Therefore, the number of moles of chloride ions present in the solution is:
0.0227 moles of GaCl3 * 3 = 0.0681 moles of chloride ions
Finally, we can calculate the mass of chloride ions present in the solution:
Mass = number of moles * molar mass
Mass = 0.0681 moles * 35.45 g/mol = 2.41 grams
Therefore, there are 2.41 grams of chloride ions present in 100 mL of a 0.227 M solution of GaCl3.