Calculate the molarity of a solution prepared by dissolving 13.0 g
of Na2CrO4
in enough water to produce a solution with a volume of 800. mL
To calculate the molarity of the solution, we first need to determine the number of moles of Na2CrO4 present in the 13.0 g of the compound.
1. Calculate the molar mass of Na2CrO4:
Na: 22.99 g/mol (atomic mass of Na)
Cr: 51.99 g/mol (atomic mass of Cr)
O: 16.00 g/mol (atomic mass of O)
Molar mass of Na2CrO4 = 2(22.99) + 51.99 + 4(16.00) = 161.97 g/mol
2. Calculate the number of moles of Na2CrO4 in 13.0 g:
Number of moles = mass / molar mass
Number of moles = 13.0 g / 161.97 g/mol ≈ 0.080 moles
3. Calculate the volume of the solution in liters:
Volume = 800 mL = 0.8 L
4. Calculate the molarity of the solution:
Molarity = moles / volume
Molarity = 0.080 moles / 0.8 L = 0.10 mol/L or 0.10 M
Therefore, the molarity of the solution prepared by dissolving 13.0 g of Na2CrO4 in enough water to produce a solution with a volume of 800 mL is 0.10 M.