Consider the following data:
19 10 9 8 14 11 11 12 11 9 19 19
17 10 13 18 16 17 5 14 11 15 18 12
8 7 10 16 2 12
Construct a frequency distribution by making the class width 3 and the lower limit of the first class 2.
Intervals / Intervalle Class Midpoints / Klasmiddelpunte Frequencies / Frekwensies Cumulative frequency / Kumulatiewe frekwensies Relative frequency / Relatiewe frekwensie
[ - )
[ A - ) D H J
[ - ) F
[ - B ) K
[ - ) E I
[ - ) G
Total C
What is the value of J in the table?
a)6.7
b)3.3
c)23.3
d)26.7
To find the value of J, we need to calculate the cumulative frequency up to interval D.
The frequencies given in the data are: 19, 10, 9, 8, 14, 11, 11, 12, 11, 9, 19, 19, 17, 10, 13, 18, 16, 17, 5, 14, 11, 15, 18, 12, 8, 7, 10, 16, 2, 12.
The cumulative frequency for interval D is the sum of the frequencies up to interval D, which includes the frequencies from intervals [A - B), [B - C), and [C - D).
Adding up these frequencies: 19 + 10 + 9 + 8 + 14 + 11 + 11 + 12 + 11 + 9 + 19 + 19 + 17 + 10 + 13 + 18 + 16 = 210
Therefore, the value of J is:
J = 210
The value of J is 210.