A ball of iron with a mass of 252 g was heated using 2263 J of energy. The initial temperature was 547 °C . What was the final temperature of the iron? (The specific heat capacity for iron is 0.449 Jg°C .) (1 point) Responses
567 °C
−527°C
24.8 °C
0.04 °C
To solve this problem, we can use the formula:
Q = mcΔT
Where:
Q = energy
m = mass
c = specific heat capacity
ΔT = change in temperature
We can rearrange the formula to solve for ΔT:
ΔT = Q / mc
Given values:
m = 252 g = 0.252 kg
Q = 2263 J
c = 0.449 J/g°C = 449 J/kg°C
Now plug in the values:
ΔT = 2263 / (0.252 * 449)
ΔT ≈ 20.18 °C
Now, to find the final temperature:
Final temperature = Initial temperature + ΔT
Final temperature = 547 °C + 20.18 °C
Final temperature ≈ 567.18 °C
Therefore, the final temperature of the iron is approximately 567 °C. So the correct answer is:
567 °C