A commercial rubbing alcohol contains 63. g of isopropanol and 0.331 g of sucrose octaacetate in each 77. -mL portion. Calculate the
concentration for each component. Be sure each of your answer entries has the correct number of significant figures.
Part 1 of 2
weight
percent
volume
%
weight
volume
isopropanol
weight percent = (mass of isopropanol / total mass) * 100
= (63. g / 63.331 g) * 100
= 99.53%
volume percent = (volume of isopropanol / total volume) * 100
= (63. mL / 77. mL) * 100
= 81.82%
weight/volume = mass of isopropanol / total volume
= 63. g / 77. mL
= 0.818 g/mL