Given P, left bracket, A, right bracket, equals, 0, point, 1, 2P(A)=0.12, P, left bracket, B, right bracket, equals, 0, point, 3P(B)=0.3 and P, left bracket, A, union, B, right bracket, equals, 0, point, 3, 3, 4P(A∪B)=0.334, find the value of P, left bracket, A, intersection, B, right bracketP(A∩B), rounding to the nearest thousandth, if necessary.
To find P(A∩B), we can use the formula:
P(A∪B) = P(A) + P(B) - P(A∩B)
Substitute the given values in the equation:
0.334 = 0.12 + 0.3 - P(A∩B)
0.334 = 0.42 - P(A∩B)
P(A∩B) = 0.42 - 0.334
P(A∩B) = 0.086
Therefore, the value of P(A∩B) is 0.086.