A ball of iron with a mass of 252 g was heated using 2263 J of energy. The initial temperature was 547 °C . What was the final temperature of the iron? (The specific heat capacity for iron is 0.449 Jg°C .) (1 point) Responses − 527 °C − 527 °C 24.8 °C 24.8 °C 0.04 °C 0.04 °C 567 °C
To find the final temperature of the iron, we can use the formula:
Q = mcΔT
Where:
Q = heat added (2263 J)
m = mass of iron (252 g)
c = specific heat capacity of iron (0.449 J/g°C)
ΔT = change in temperature (Tf - Ti)
First, let's calculate the change in temperature:
2263 J = (252 g) * (0.449 J/g°C) * (Tf - 547°C)
2263 J = 112.848 Tf - 61644
2263 J + 61644 = 112.848 Tf
Tf = 63807 / 112.848
Tf ≈ 565.06 °C
Therefore, the final temperature of the iron was approximately 565.06 °C. So the closest option is 567 °C.