When Cu(OH) is heated, it decomposes to black CuO and H20. How many grams of CuO will be formed from the decomposition of 6.59 g of Cu(OH),?
To solve this problem, we need to first determine the molar masses of Cu(OH) and CuO.
Cu(OH):
Cu = 63.55 g/mol
O = 16.00 g/mol
H = 1.01 g/mol
Molar mass of Cu(OH) = 63.55 + 16.00 + 1.01 = 80.56 g/mol
CuO:
Cu = 63.55 g/mol
O = 16.00 g/mol
Molar mass of CuO = 63.55 + 16.00 = 79.55 g/mol
Next, we need to determine the number of moles of Cu(OH) in 6.59 g:
moles = mass / molar mass
moles = 6.59 g / 80.56 g/mol ≈ 0.082 moles
According to the balanced chemical equation of the decomposition reaction:
Cu(OH) → CuO + H2O
1 mole of Cu(OH) produces 1 mole of CuO
Therefore, 0.082 moles of Cu(OH) will produce 0.082 moles of CuO.
Finally, we can calculate the mass of CuO formed from 0.082 moles:
mass = moles x molar mass
mass = 0.082 moles x 79.55 g/mol ≈ 6.52 g
Therefore, the mass of CuO formed from the decomposition of 6.59 g of Cu(OH) is approximately 6.52 grams.