how many more square inches of paint is required to cover a ball whose radius is 58 inches then a ball whose radius is 22 inches?
To find the difference in square inches of paint required to cover the two balls, we first need to calculate the surface area of each ball.
The formula for the surface area of a sphere is 4πr^2, where r is the radius of the sphere.
For the ball with a radius of 58 inches:
Surface area = 4π(58)^2 = 4π(3364) = 13456π square inches
For the ball with a radius of 22 inches:
Surface area = 4π(22)^2 = 4π(484) = 1936π square inches
The difference in square inches of paint required to cover the two balls is:
13456π - 1936π = 11424π square inches
Therefore, 11424π square inches more paint is required to cover a ball with a radius of 58 inches compared to a ball with a radius of 22 inches.