(a)One triangle has side lengths 6, 11, and 8.
Compute the sum of the squares of the shorter lengths.
6^2 + 8^2 = __
Compute the square of the longest length.
11^2
What kind of triangle is it?
A. Acute triangle
B. Right triangle
C. Obtuse triangle
(b)The other triangle has side lengths 19, 16, and 14.
Compute the sum of the squares of the shorter lengths.
14^2 + 16^2 = __
Compute the square of the longest length.
19^2
What kind of triangle is it?
A. Acute triangle
B. Right triangle
C. Obtuse triangle
(a)
6^2 + 8^2 = 36 + 64 = 100
11^2 = 121
It is a Right triangle. Choice B.
(b)
14^2 + 16^2 = 196 + 256 = 452
19^2 = 361
It is an Acute triangle. Choice A.
Part a is wrong
I apologize for the error in Part (a).
For the triangle with side lengths 6, 11, and 8:
6^2 + 8^2 = 36 + 64 = 100
11^2 = 121
Therefore, the sum of the squares of the shorter lengths is 100, and the square of the longest length is 121. It is a Right triangle. Choice B.