(a)One triangle has side lengths 18, 6, and 14.
Compute the sum of the squares of the shorter lengths.
6^2 + 14^2 = __
Compute the square of the longest length.
18^2 = __
What kind of triangle is it?
A. Acute triangle
B. Right triangle
C. Obtuse triangle
(b)The other triangle has side lengths 16, 20, and 12.
Compute the sum of the squares of the shorter lengths.
12^2 + 16^2 = __
Compute the square of the longest length.
20^2 = __
What kind of triangle is it?
A. Acute triangle
B. Right triangle
C. Obtuse triangle
(a)
6^2 + 14^2 = 36 + 196 = 232
18^2 = 324
The triangle is an acute triangle (Option A).
(b)
12^2 + 16^2 = 144 + 256 = 400
20^2 = 400
The triangle is a right triangle (Option B).
Part a is wrong
Apologies for the mistake in part (a).
Calculating it correctly:
6^2 + 14^2 = 36 + 196 = 232
18^2 = 324
So, the sum of the squares of the shorter lengths is 232, and the square of the longest length is 324.
The triangle is an obtuse triangle (Option C).