If you flip two coins simultaneously, what's the probability you'll have to flip them four times before the first occurrence of two heads?
A. 14
B. .188
C. .25
D. 11
E. .683
The probability of getting two heads when flipping two coins simultaneously is 1/4, as there are four possible outcomes (HH, HT, TH, TT) and only one of them is two heads (HH).
The probability of not getting two heads in the first three flips is 3/4 (the opposite of getting two heads). To calculate the probability of having to flip them four times before the first occurrence of two heads, we multiply the probability of not getting two heads in the first three flips by the probability of getting two heads on the fourth flip:
(3/4) x (1/4) = 3/16
So, the probability of having to flip them four times before the first occurrence of two heads is 3/16, which is approximately 0.188 or .188. Therefore, the answer is B. .188.