Solve the system of equations.
3x−4y=40
5x−5y=55
To solve this system of equations, we can use the method of substitution or elimination.
Let's use the method of substitution.
From the first equation, we can isolate x:
3x - 4y = 40
3x = 4y + 40
x = (4y + 40) / 3
Now substitute this expression for x into the second equation:
5((4y + 40) / 3) - 5y = 55
(20y + 200) / 3 - 5y = 55
20y + 200 - 15y = 165
5y + 200 = 165
5y = -35
y = -7
Now substitute y = -7 back into the first equation to solve for x:
3x - 4(-7) = 40
3x + 28 = 40
3x = 12
x = 4
Therefore, the solution to the system of equations is x = 4 and y = -7.