The first term of a linear sequence is 5 and the common difference is minis 3 find the 15th term of the sequence
To find the 15th term of the linear sequence, we can use the formula for the nth term of an arithmetic sequence:
\[a_n = a_1 + (n-1)d\]
where:
- \(a_n\) is the nth term of the sequence
- \(a_1\) is the first term of the sequence
- \(d\) is the common difference between the terms
- \(n\) is the term number we want to find
Given that the first term (\(a_1\)) is 5 and the common difference (\(d\)) is -3, we can plug these values into the formula:
\[a_{15} = 5 + (15-1)(-3)\]
\[a_{15} = 5 + 14(-3)\]
\[a_{15} = 5 - 42\]
\[a_{15} = -37\]
Therefore, the 15th term of the sequence is -37.