find the sum
(2x^2+5x-7)+(3-4x^2+6x)
First, combine like terms:
(2x^2 + 5x - 7) + (3 - 4x^2 + 6x)
= 2x^2 + 5x - 7 + 3 - 4x^2 + 6x
= 2x^2 - 4x^2 + 5x + 6x - 7 + 3
= -2x^2 + 11x - 4
So, the sum is -2x^2 + 11x - 4.
(2x^2+5x-7)+(3-4x^2+6x)
(2x^2 + 5x - 7) + (3 - 4x^2 + 6x)
= 2x^2 + 5x - 7 + 3 - 4x^2 + 6x
= 2x^2 - 4x^2 + 5x + 6x - 7 + 3
= -2x^2 + 11x - 4
So, the sum is -2x^2 + 11x - 4.