The sum of a finite geometric series S100=1−0.05^100/1−0.05 can be expressed in sigma notation with the following variables: Find n and a. (2 points)
To express the sum of a finite geometric series in sigma notation, we need to identify the values of n and a.
For the series S100=1−0.05^100/1−0.05, we have:
a = 1
r = 0.05
n = 100
Therefore, the sum can be expressed in sigma notation as:
Σ_{k=0}^{99} 1(0.05)^k
where a = 1 and n = 100.