How would you write the series 3+12+48+192 using sigma notation?(1 point) Responses ∑4n=1(3)(4)n−1 sigma-summation underscript n equals 1 overscript 4 End Scripts left parenthesis 3 right parenthesis left parenthesis 4 right parenthesis superscript n minus 1 baseline ∑4n=1(4)(3)n−1 sigma-summation underscript n equals 1 overscript 4 End Scripts left parenthesis 4 right parenthesis left parenthesis 3 right parenthesis superscript n minus 1 baseline ∑3n=1(3)(4)n−1 sigma-summation underscript n equals 1 overscript 3 End Scripts left parenthesis 3 right parenthesis left parenthesis 4 right parenthesis superscript n minus 1 baseline ∑4n=1(3)(−4)n−1 sigma-summation underscript n equals 1 overscript 4 End Scripts left parenthesis 3 right parenthesis left parenthesis negative 4 right parenthesis superscript n minus 1 baseline

∑4n=1(3)(4)^(n-1)