a scientist heats 30 grams of calcium carbonate (CaCO3) in the chemical reaction shown what is the total mass of the products
The chemical reaction for the decomposition of calcium carbonate is:
CaCO3 (s) -> CaO (s) + CO2 (g)
The molar mass of CaCO3 is 100.09 g/mol. This means that 30 grams of CaCO3 is approximately 0.3 moles.
From the balanced chemical equation, we can see that 1 mole of CaCO3 produces 1 mole of CaO and 1 mole of CO2. Therefore, 0.3 moles of CaCO3 will produce 0.3 moles of CaO and 0.3 moles of CO2.
The molar mass of CaO is 56.08 g/mol and the molar mass of CO2 is 44.01 g/mol.
Therefore, the total mass of the products will be:
(0.3 moles CaO x 56.08 g/mol) + (0.3 moles CO2 x 44.01 g/mol) = 16.82 g + 13.20 g = 30.02 g
Therefore, the total mass of the products will be approximately 30.02 grams.