Solve
8x -4y = -28
2x - 6y = 8
To solve this system of equations, we can use the method of substitution or elimination.
Let's use the method of substitution:
From the second equation, we can solve for x in terms of y:
2x - 6y = 8
2x = 6y + 8
x = 3y + 4
Now substitute x = 3y + 4 into the first equation:
8(3y + 4) - 4y = -28
24y + 32 - 4y = -28
20y + 32 = -28
20y = -60
y = -3
Now substitute y = -3 back into x = 3y + 4:
x = 3(-3) + 4
x = -9 + 4
x = -5
Therefore, the solution to the system of equations is x = -5 and y = -3.