Roy decided to wrap a bowling ball as a present for his best friend. The bowling ball has a circumference of 18 inches. Assuming there is no overlap, how much wrapping paper will Roy need? Round to the nearest whole unit where necessary
The formula to calculate the surface area of a cylinder is:
Surface Area = 2 * π * r * h + 2 * π * r^2
Given that the circumference of the bowling ball is 18 inches, we can calculate the radius (r) using the formula for circumference:
Circumference = 2 * π * r
18 = 2 * π * r
r = 18 / (2 * π) ≈ 2.86 inches
Given that the height (h) of the bowling ball is equal to its diameter, which is twice the radius:
h = 2 * 2.86 ≈ 5.71 inches
Now we can plug these values into the surface area formula:
Surface Area = 2 * π * 2.86 * 5.71 + 2 * π * 2.86^2 ≈ 161.24 square inches
Therefore, Roy will need approximately 161 square inches of wrapping paper.