A circular swimming pool has a diameter of 8.6 m. It is filled with water to a height of 1.6 metres. How much water is in the pool, to the nearest hundred litres? Hint: 1000 L = 1 m3.
First, we need to calculate the volume of the pool.
The formula to calculate the volume of a cylinder is V = πr^2h, where r is the radius of the cylinder and h is the height.
Since the diameter of the pool is 8.6m, the radius (r) is half of the diameter, so r = 8.6m / 2 = 4.3m.
The height (h) of the water in the pool is 1.6m.
Now we can calculate the volume of the pool:
V = π(4.3)^2(1.6)
V ≈ π(18.49)(1.6)
V ≈ 29.58π
V ≈ 92.98 m^3
Now, to convert the volume from cubic meters to litres, we use the conversion factor 1 m^3 = 1000 L:
Volume in litres = 92.98 m^3 x 1000 L/m^3 ≈ 92,980 L
Therefore, there are approximately 92,980 litres of water in the pool.