A helium balloon is at a height of 1,200 after two minutes in flightThe balloon finally pops after seven minutes in flight, at a height of 10,500 ftWhat is the average rate of change in height for the balloon over this period of time? (1 point) 9, 300fL / m * in; 1,033.33 ft./min.; 1, 860fL / m * in; 2.34fL / m * in
The average rate of change in height for the balloon can be calculated by dividing the total change in height by the total time.
Total change in height = 10,500 ft - 1,200 ft = 9,300 ft
Total time = 7 minutes - 2 minutes = 5 minutes
Average rate of change in height = 9,300 ft / 5 min = 1,860 ft/min
Therefore, the average rate of change in height for the balloon over this period of time is 1,860 ft/min.