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What are all the real zeroes of y=(x–12)3–7
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To find the real zeroes of the equation y=(x-12)^3 - 7, we need to set y equal to zero and solve for x.
0 = (x-12)^3 - 7
Adding 7 to both sides:
7 = (x-12)^3
Taking the cube root of both sides:
∛7 = x-12
Adding 12 to both sides:
x = 12 + ∛7
Therefore, the real zero of the equation is x = 12 + ∛7.