Question
What is the distance between (19,−6) and (8,−6) on a coordinate plane?(1 point)
units
The distance between (19,-6) and (8,-6) on a coordinate plane is 11 units.
To calculate this distance, we can use the formula for the distance between two points in a plane:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Plugging in the coordinates of the two points:
Distance = sqrt((8 - 19)^2 + (-6 - (-6))^2)
Distance = sqrt((-11)^2 + (0)^2)
Distance = sqrt(121 + 0)
Distance = sqrt(121)
Distance = 11
Therefore, the distance between (19,-6) and (8,-6) on a coordinate plane is 11 units.