Use the equation for the formation of water to answer the question. 2H2 + O2 → 2H2O Elements such as oxygen and hydrogen naturally exist as diatomic molecules (i.e., in a paired-atom form). Does the equation for the formation of water violate the law of conservation of mass? Why or why not? (1 point) Responses No, it does not because there are two water molecules, so the bonds within the diatomic molecules were not broken. No, it does not because there are two water molecules, so the bonds within the diatomic molecules were not broken. Yes, it does because the diatomic oxygen molecule is not present on both sides of the equation. Yes, it does because the diatomic oxygen molecule is not present on both sides of the equation. No, it does not because the number and mass of atoms are conserved even though the number of molecules is not. No, it does not because the number and mass of atoms are conserved even though the number of molecules is not. Yes, it does because there are two oxygen atoms in the reactants and only one in the product.
No, it does not because the number and mass of atoms are conserved even though the number of molecules is not. Each oxygen atom in the diatomic oxygen molecule is still present in the water molecules formed. The equation follows the law of conservation of mass.
