A new high school opened in 2018 with an initial enrollment of 1,500 students. The number of students attending, S , grows as a linear function of time, t, where t is the number of years since the school’s opening. In 2022, there were 1,900 students enrolled. Sketch a graph of the situation. Where would you place the y-intercept?
(0, 1,500)
(1,900, 0)
(0, 1,900)
(1,500, 0)
The correct option is (0, 1,500).
The y-intercept represents the initial enrollment when the school opened in 2018, which was 1,500 students. This means that at t = 0 (the y-intercept), there were 1,500 students enrolled.
Therefore, the correct point for the y-intercept is (0, 1,500) on the graph.