Solve the system of equations by elimation
12x-10y=2
-6x+7y=-11
To solve the system of equations by elimination, we need to get the coefficients of either the x or y terms to be the same in both equations.
1. Multiply the second equation by 2:
-6x + 7y = -11
-12x + 14y = -22
2. Add the two equations together to eliminate x:
(12x - 10y) + (-12x + 14y) = 2 - 22
4y = -20
3. Divide by 4 to solve for y:
y = -5
4. Substitute y back into either equation to solve for x. Let's use the first equation:
12x - 10(-5) = 2
12x + 50 = 2
12x = -48
x = -4
Therefore, the solution to the system of equations is x = -4 and y = -5.