an elastic cord can be streached to iys elastic limit of load 2N.if a 35cm lenghth of the cord is extended 0.6cm by a force of 9
0.6cm by a force of 0.5N, what will the length of the cord when the streaching force is 2.5N?
A. 350.8cm B.352.8cm
C. 353.0cm D.356 cm
E.Cannot be determimed by the data given.
To find the new length of the cord when the stretching force is 2.5N, we first need to calculate the extension constant for the cord.
Extension constant, k = (F2 - F1) / (L2 - L1)
k = (0.5N - 2N) / (0.6cm - 0cm)
k = -1.5N / 0.6cm
k = -2.5N/cm
Now we can use this extension constant to find the new length of the cord when the stretching force is 2.5N:
L2 = L1 + k * (F2 - F1)
L2 = 35cm + (-2.5N/cm) * (2.5N - 0.5N)
L2 = 35cm + (-2.5N/cm) * 2N
L2 = 35cm - 5cm
L2 = 30cm
Therefore, the new length of the cord when the stretching force is 2.5N is 30cm.
Ans: E. Cannot be determined by the data given.