A force of two newton dtreces an elastic material by 30. What additional force will elast the material 35cm assum elastic limit is not preasent
To stretch the material by an additional 35 cm, we can use Hooke's Law which states that the force exerted by an elastic material is directly proportional to the amount it is stretched.
Given:
Initial force = 2 N
Initial stretch = 30 cm = 0.3 m
Additional stretch = 35 cm = 0.35 m
We can set up the proportion:
2 N / 0.3 m = F / 0.35 m
Now, solve for F (the additional force):
F = (2 N / 0.3 m) * 0.35 m
F = 2.33 N
Therefore, an additional force of 2.33 Newtons is required to stretch the elastic material by an additional 35 cm.