To show that the system of equations has one solution, we need to find values of x that satisfy both equations.
For the first equation, 4x + 22 = 8x + 10, let's choose an arbitrary value of x and plug it in:
Let x = 2:
4(2) + 22 = 8(2) + 10
8 + 22 = 16 + 10
30 = 26
As 30 does not equal 26, this value of x does not satisfy the first equation.
For the second equation, 3x + 18 = 5x + 8, let's similarly choose an arbitrary value of x and plug it in:
Let x = 1:
3(1) + 18 = 5(1) + 8
3 + 18 = 5 + 8
21 = 13
Again, 21 does not equal 13, so this value of x does not satisfy the second equation.
Therefore, we cannot find values of x that satisfy both equations simultaneously, indicating that the system of equations does not have one solution.
make tis lik a 8th grader wrote it
To solve the system of equations, we gotta find some numbers for x that work in both equations.
In the first equation, when we plug in x=2, it doesn't work out because 30 is not the same as 26.
In the second equation, when we plug in x=1, it also doesn't work because 21 is not the same as 13.
Since we couldn't find one number that works for both equations, that means the system of equations doesn't have just one solution.